Low Pass Filter and Capactior?

In a low pass CR circuit the output appears across the capacitor.

If you want to reduce the signal by one tenth then the capacitive reactance will need to be 6 Ohms and if you want to make it one hundredth then it will need to be 0.6 Ohms.

Xc = 1/(2 x pi x f x C)

C = 1/(2 x pi x f x Xc)

For attenuation of 1/10 then we require Xc to be 6 Ohms

C =1/(2 x 3.142 x 2000 x 6) F

C = 1/75398

C = 1.3 x 10^-5 F

C =13 uF

For attenuation of 1/100 then we require Xc to be .6 Ohms

C =1/(2 x 3.142 x 2000 x .6) F

C = 1/7539

C = 1.3 x 10^-4 F

C =133 uF

Typically, these high values of capacitance require the use of electrolytic and they don't like ac. So you are looking to use a non electrolytic type of capacitor and the bigger the value you choose to use the more bulky it is likely to be. You can get 1 uF NON- electrolytic easily enough but you are going to need at least 13 in parallel to reduce the signal by 1/10th.