Yahoo Clever wird am 4. Mai 2021 (Eastern Time, Zeitzone US-Ostküste) eingestellt. Ab dem 20. April 2021 (Eastern Time) ist die Website von Yahoo Clever nur noch im reinen Lesemodus verfügbar. Andere Yahoo Produkte oder Dienste oder Ihr Yahoo Account sind von diesen Änderungen nicht betroffen. Auf dieser Hilfeseite finden Sie weitere Informationen zur Einstellung von Yahoo Clever und dazu, wie Sie Ihre Daten herunterladen.

Naim P fragte in Science & MathematicsPhysics · vor 1 Jahrzehnt

What is the answer to this buoyancy question? Please explain every step.?

What is the buoyancy force, exercised on a floating whip by the surrounding water, whose mass is 20'000kg?

Update:

What if the ship will sink?

1 Antwort

Relevanz
  • vor 1 Jahrzehnt
    Beste Antwort

    When an object, any object, floats, the buoyancy B = W the weight of the object. Thus, the weight of the ship is W = mg = 20000*9.81 = 19.6 X 10^4 Newtons = B is the buoyancy.

    If the object sinks, the buoyancy B = rho g V; where rho is the density of the water (e.g., 1 kg/L for fresh water), g = 9.81 m/sec^2, and V is the volume of the water displaced by the sinking object. If V = Ah, where A is the cross sectional area of the ship, then h is the depth the ship sinks into the water. If h >= H, the height of the ship, then the entire ship is immersed.

    When W > B, the ship will sink because there is insufficient buoyancy to keep it afloat. In which case we know that the buoyancy is less than the weight of the ship cited earlier. We can write W > rho g V and solve for V < W/(rho g) to find out how much water the ship can displace and still sink. But without knowing the volume of water displaced by the sunk ship, we cannot get an exact number of the buoyancy.

Haben Sie noch Fragen? Jetzt beantworten lassen.