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Photons passing a field?
What happens to a beam of photons passing an electric field?
And when it goes through a magnetic field?
(direction, polarisation, frequence change, other effects ???)
Thanks everybody. All your answers were very interesting.
7 Antworten
- alooo...Lv 4vor 2 JahrzehntenBeste Antwort
A photon is a quantum of the vibrational energy of the space grid (as in the image above). At any one point on the wave, photons are produced out of the zero-point and then oppositely, photon holes are produced. Hence, it must be the case that these oscillations up and down come in discrete steps--or quanta.
When a particle from the quantum vacuum acquires energy from a charged particle of matter, it may expand from the addition of this excitation energy to become an ordinary photon. Energy, therefore, expands the size of a virtual photon in ground state.
A virtual photon, thus, is a "collapsed" short-range quantum that becomes an ordinary photon when given energy from an excited charged particle. Hence, the primary reason that we do not observe the photons that exist in the quantum vacuum, is because the quanta of space-time that compose the vacuum have a very minute amount of energy within them and are, therefore, too small to be observed directly. However, such vacuum quanta may become observable and measurable as ordinary photons after emission.
When actualization takes place, we may measure photons and photonic energy hitting a measuring device. But, while in-flight, we may not speak about photons at all, because technically speaking they are not photons. So, when Planck's equation says that energy comes in lumps E = hf, this only refers to a state of an EM wave after an actualization or measurement has happened. Prior to this we have only Kant's noumenal "wave" condition.
photons must have higher frequencies, by exactly one hertz, than the expected difference of the energy levels of the electrons from which they received energy. Additionally, photon wavelengths must include a very long 3 x 10^8 meters to be added to all emitted wave fronts
- vor 2 Jahrzehnten
Electromagnetic radiation transfers energy from one place to another, even through the vacuum of empty space. It is self-perpetuating, like a perfect pendulum, that swings back and forth forever. And just like two puppies playing tug of war with a toy, repeatedly pulling on it at the same time, because each senses the pull from the other, the electric and magnetic fields oscillate. When the electric field gets stronger, the magnetic field instantly strengthens too, and when the electric field weakens, so does the magnetic field.The refraction index of any material is the property that causes light to bend when the light hits its surface at any angle, other than perpendicular. This index depends upon the wavelength of the light. This fact can be used to resolve the light beam into the spectral components it consists of. One of the tools used for spectrum analysis of light is the glass prism.
- mathematicianLv 7vor 2 Jahrzehnten
Since Maxwell's equations are linear, there is no effect on a light wave as it passes through an electric field (or a magnetic one, for that matter). Only at very intense fields (where particle-antiparticle pair production is significant) are there non-linearlities that can affect passing light.
- Anonymvor 2 Jahrzehnten
Math is absolutely right just to conplement:
photons are quantum eletric and magnetic fields you can have the efect Math tells you about, creation of particules anti particules with intensities higher then 10E18W which are not possible yet. However if you have a non linear material ( the most comom are crystals, you can have several efects, harmonic generation frequency drift polarization change ...
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- ag_iitkgpLv 7vor 2 Jahrzehnten
Photons are not affected by electric or magnetic fields. However, they are affected by strong gravitational fields.