Latent Heat Physics Question!!?

Question

I'm utterly confused right now. 

The question goes: 500 grams of Ice at 0 degrees Celsius is melted into 500 grams water at 0 degrees Celsius.  How much heat energy is required to do this? 

Okay, that's nice. Now what was I given to solve this? 

A formula:   l = Delta Q/ m

Or rather: Q = heat added
so  

Change in heat added / mass gives me latent heat. 

Alright, but what change in heat added? How does that even correlate with this question? 
I could make it change in heat. But I don't know how much heat was added or what the change was. That's the question. 

If I were to rearrange for Delta Q, I get Delta Q = Latent Heat * mass. 

But what is it's latent heat? 

It makes no sense in my mind. I already checked the material he gave us and this formula is about the extent of it when it comes to latent heat.

Madhukar · Accepted Answer

Latent heat of fusion of water = 80 cal/g
=> it requires 80 cal of heat to melt 1 g of ice at 0° C to water at 0° C
=> Total heat needed to melt 500 g of ice
= 500 * 80 cal
= 40,000 cal
= 40 kcal.

morken · Answer

You ought to bear in mind it in three steps. 1) The warmth wanted to warm the ice from -10 C to 0 C. 2) The warmth needed to melt the ice. 3) The warmness needed to heat the water from zero C to 90 C. To do steps 1 and three you'll need the targeted warmness capacity of ice and liquid water respectively.

Latent Heat Physics Question!!?

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