Help solving a problem involving wavelengths?

Question

TV channel 2 broadcasts in the frequency range 51  to 59 MHz. What is the corresponding range of wavelengths? (Let us denote the minimum and maximum wavelengths by λmin and λmax, respectively.)

Kevin · Accepted Answer

Well
Frequency = Speed of light / Wavelength

Therefore
Wavelength = Speed of light / Frequency

Wavelength if inversely proportional with Frequency
When frequency increases ... wavelength decreases
And vice versa

So,
Max wavelength is at 51 MHz
Therefore 
Max Wavelength = (3 * 10^8) / (51 * 10^6)
Max Wavelength = 5.88 m

Min wavelength is at 59 MHz
Therefore
Min Wavelength = (3 * 10^8) / (59  * 10^6)
Min Wavelength = 5.08 m

==============

Note:
Channel 2 is in the VHF (low) band 
Its frequency is between (54 - 60 MHz)

BUT i made my calculations according to your given frequencies

i hope you understood

Help solving a problem involving wavelengths?

1 Antwort