simple geometry question...?

What you have is a right triangle with 90, 45, 45 angles.

The third line for which you have a value is the hypotenuse, h.

you can solve for the base, the adjacent leg (b), and the height, the opposite leg (a) by using the following formulas:

Sin 45 degree = opposite / hypotenuse = a / h

Cos 45 degree = adjacent / hypotenuse = b / h

once you find

This is a 45-45-90 right triangle, with sides in the ratio of 1:1:sqrt2, so the two short sides are of equal length. Just divide the third, or long side by 1.414 and you will get the answer correct to three decimal places.

You can use the 'sohcahtoa' rule as it is a 90 degree angle, so you need a scientific calculator. You know the length of the hypontenuse (third line) and you know an angle (45degrees).

As it is a 45 degree angle, that means the other unknown angle is 45 degrees too, and hence the two unknown lines are the same.

so...to find the length of one (and the other too)....

Length = sin45 x hypotenuse.

sin 45 = 1/ square root of two =0.7071 if that helps, esp if you dont have a scientific calculator!

so in summary......multiply the length of the third line by 0.7071!!!!

:)

a^2 + b^2 = c^2

In this case, sides a & b are equal, because you have a 45-45-90 triangle.therefore, your pythagorean can change to

2a^2 = c^2, where "c" = the length of the hypoteneuse that you know.

HTH