Help with math problem please.?

You have 2 equations, 3 variables: C for number of chickens, G for goats, W for cows. You have an equation for the body count and one for the money:

C + G + W = 100

.5C + 3.5 G + 10W = 100

multiply 2nd equation by 2 to get rid of fractions:

C + G + W = 100

C + 7G + 20W = 200

subtract 1st from 2nd:

6G + 19W = 100, and solve it for G:

G = (100 - 19W)/6

while that has infinitely many solutions, we need G to be a whole number, so there's only 1 solution:

19(4) = 76, 100-76 = 24, 24/6 = 4 goats.

so then it's 4 cows, 92 chickens, and only the 1 solution.

40 chickens .50 x 40= $20

20 Goats 3.50 x 20= $70

1 Cow $10

$100.00

If x be the number of chickens, y the number of goats and z the number of cows, we can write:

0.5x + 3.5y + 10z = 100

Also x + y + z = 100 (number of animals)

We have three variables and only two equations. So, we cannot solve for definite values of x, y and z.

Yes, multiple solutions are possible to satisy that one equation.

I won't solve it for you but I'll get ou started. Set up an equation:

C= chickens

G= goats

W= cows

100= .5C + 3.5G + 10W

the 100 is what he spends

the .5, 3.5 and 10 represent the cost of each noted animal

to get rid of the .5 and 3.5 and make this problem easier you can mult. everything by 10

1000= 5C + 35G + 100W

reduce the problem

200= C + 7G + 20W

now you need to slove for each variable C, G and W, which you should know how to do and yes it takes some effort.

lots of possibilities

for example 4 cows 40

10 goats 35

leaves25 dollars to buy 50 chickens

9 cows 90

1 goat 3.50 makes 93.50 and leave 6.50 for 13 chickees

let no. of chicken ,goats and cows be a , b and c then :

a+b+c=100

and

0.5a+3.5b+10c=100

there are three variables and two equations so no unique solution will be written .

there will be more than one combination .

Four cows, four goats, and ninety-two chickens is the only combination possible.

Just say he bought a horse for $100 and call it even.

Paul Ding is correct

There is nooooooo way I am doing a math problem if I don't have to. Get a tutor, or ask your teacher.