🐟 Fish 🐟
Beste Antwort
S = Vektor Weg
S0 = Startvektor
V = Geschwingigkeitsvektor
G = Gravitation Vektor beachte G = (0,-g) da nach unten gerichtet
Weg:
Schiefer Wurf:
S = S0 + V*t + G*t²/2
s(t) = (x0,y0) + (cos(α)*|v|,sin(α)*|v|)*t + (0,-g)*t²/2
s(t) = (x0,y0) + (cos(α)*|v|*t,sin(α)*|v|*t) + (0,-gt²/2)
s(t) = (x0+cos(α)*|v|*t,y0+sin(α)*|v|*t-gt²/2)
also
sx = x0+cos(α)*|v|*t
sy = y0+sin(α)*|v|*t-gt²/2
horizontaler Wurf α = 0
S=S0 + V*t + G*t²/2
s(t) = (x0,y0) + (1*|v|,0*|v|)*t + (0,-g)*t²/2
s(t) = (x0,y0) + (1*|v|*t,0*|v|*t) + (0,-gt²/2)
s(t) = (x0,y0) + (|v|*t,0) + (0,-gt²/2)
s(t) = (x0+|v|*t,y0-gt²/2)
also
sx = x0+|v|
sy = y0-gt²/2
Geschwindigkeit v(t) entsprechend
v(t) = (cos(α)*|v|,sin(α)*|v|) + (0,-g*t)
v(t) = (cos(α)*|v|,sin(α)*|v|-g*t)
vx = cos(α)*|v|
vy = sin(α)*|v|-g*t
für α=0 horizontaler Wurf
v(t) = (cos(α)*|v|,sin(α)*|v|-g*t)
v(t) = (1*|v|,0*|v|-g*t)
vx = |v|
vy = -g*t