What exactly is the relationship between surface area and available amperage in a rechargeable lead acid battery?

Okay so I've guessed that it basically is; more surface area of the lead plates, more amperage; perhaps in a roughly linear relationship, but what I want to know are the specifics.  So in a fairly typical deep cycle lead-acid battery, there are six cells with no load each cell has a charge of about 2.23 volts, and given a load of X number of ohms, it can deliver such-and-such an amperage for a given time...but I want to know a constant, and maybe also a formula that uses Square Meters of lead plate, acid concentration, Amps under load, etc. to calculate how much surface area will deliver how much current.