Molarity of 5.30g of Na2CO3 dissolved in 500mL?
.534L of a 1.50 M solution of NaCl is diluted until the V was 1L, new molarity?

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Molarity of 5.30 g of Na₂CO₃ dissolved in 500 mL ?

Molar mass of Na₂CO₃ = (23.0×2 + 12.0 + 16.0×3) g/mol = 106.0 g/mol
Number of moles of Na₂CO₃ = (5.30 g) / (106.0 g/mol) = 0.0500 mol
Molarity of Na₂CO₃ = (0.0500 mol) / (500/1000 L) = 0.100 M

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0.534L of a 1.50 M solution of NaCl is diluted until the V was 1L, new molarity?

M₁ V₁ = M₂ V₂
Then M₂ = M₁ × (V₁/V₂)

New molarity = (1.50 M) × (0.534/1) = 0.8 M

Molarity of 5.30g of Na2CO3 dissolved in 500mL? .534L of a 1.50 M solution of NaCl is diluted until the V was 1L, new molarity?

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