I am having trouble these 2 problems in Geometry. PLEASE HELP!?

1. Indicate the equation of the given line in standard form.

The line with slope 9/7 and containing the midpoint of the segment whose endpoints are (2, -3) and (-6, 5).

slope is 9/7

so you are going to start with

y=9x/7

the midpoint

(x1+x2)/2,(y1+y2)/2

for (2, -3) and (-6, 5)

(2-6)/2,(-3+5)/2

4/2,2/2

(2,1)

to get the line to pass through the point

SUBTRACT the values from their relative variable

y=9x/7

(y-1)=9(x-2)/7

y-1=9x/7-18/7

y=9x/7-18/7+7/7

y=9x/7-11/7

that's slope intercept

for standard

x+y=c

y=9x/7-11/7

multiply through by 7

get rid of the fractions

[always]

7y=9x-11

-9x+7y= -11

2. Indicate the equation of the given line in standard form.

The line through the midpoint of and perpendicular to the segment joining points (1, 0) and (5, -2).

perpendicular is the negative inverse of the reference line's slope

so

y=3/5

would become

y= -5/3

but we have to find the slope first

slope=m=rise over run=(y1-y2)/(x1-x2)

for (1, 0) and (5, -2)

(-2-0)/(5-1)

-2/4

-1/2

so the perpendicular is

2/1

you start with

y=2x

through the midpoint

(x1+x2)/2,(1+y2)/2

(1+5)/2,(0-2)/2

6/2,-2/2

3,1

SUBTRACT the values from their relative variables

y=2x

(y-1)=2(x-3)

y-2=2x-6

y=2x-4

again, that is slope intercept form

standard form:

-2x+y= -4