Details follow. What is the formula I keep forgetting involving time and distance?

Question

2 vehicles leave the same point, in the same direction, at different times and speeds. If the faster vehicle leaves last, when will it pass the first? I can work this out by trial and error but I know there is a formula which I simply can't remember and can't even derive from those I do remember. Thank you for you assistance.

? · Accepted Answer

There is a formula?  I don't like memorizing formula...

V1 is the speed of the first car
V2 is the speed advantage of the second car
V2-V1 = speed advantage of the second car.

T is the time the first car has been on the road
H is the headstart.
T-H is the time the second car has been on the road

(V2)(T-H) = (V1)(T)
V2T - V2H - AH = V1T
(V2-V1)T = (V2)H

Is that the sort of formula you are looking for?

Zaen · Answer

Distance = Speed x Time

Re-arrangable to

Speed = Distance / Time

Time = Distance / Speed

remember in order to use this formula correctly, all the values need to be in the same units. i.e. if you have kmh for the speed, your distance you calculate will be in km

Hope that helps

Anonym · Answer

Distance = Rate x Time  -- Dimensionally  --  Miles = Hrs x Miles per Hour

Dave aka Spider Monkey · Answer

distance = rate * time 

                speed sauch as mph   time (in terms of hours and minutes usually)

Sachin · Answer

S=ut+1/2(a(t^2))  YAY I ANSWERED FIRST

Details follow. What is the formula I keep forgetting involving time and distance?

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