Yahoo Clever wird am 4. Mai 2021 (Eastern Time, Zeitzone US-Ostküste) eingestellt. Ab dem 20. April 2021 (Eastern Time) ist die Website von Yahoo Clever nur noch im reinen Lesemodus verfügbar. Andere Yahoo Produkte oder Dienste oder Ihr Yahoo Account sind von diesen Änderungen nicht betroffen. Auf dieser Hilfeseite finden Sie weitere Informationen zur Einstellung von Yahoo Clever und dazu, wie Sie Ihre Daten herunterladen.
Help with math problem?
Hey, I'm trying to get a linear slope on a graph for momentum, and so I derrived this equation to help me do so.
p = m*v
1/p = m/v
Now how can I get it so p = to one against the other?
The graph needs to have Y against X, so P can't be just (mv)
How could I change it so that I've got p = something divided against something.
Would it be p = m/(1/v) ? or p = (1/m) / (1/v) ?
And is 1/ (m*v) the same as (1/m) * (1/v) ?
1 Antwort
- ?Lv 4vor 8 JahrenBeste Antwort
If p = m*v, then 1/p = 1/(m*v)
Your two equations cannot both be generally true unless the p (or the m or the v) mean different things in the two equations. If they mean different things, use different symbols. As it is, you can't have both equations always true.
