How do you find the slope of 5y=x-5?

You have to rearrange the equation so that it takes the form y = mx + b, where m is the slope and b is the y-intercetp

5y = x - 5 divide everything by 5

y = 1/5x - 1. Therefore the slope is 1/5

Divide this 5y = x - 5 by 5, the equation will become y = x / 5 - 1. The slope is 1 / 5.

First, divide by 5 on both sides of the equation to get y by itself. Assuming there is a 1in front of the x, your equation will be y=1/5x-1. In slope form y=mx+b, your m is your slope which would be 1/5 :)

You have to isolate 1xY. In other words, solve for Y. When you do, you will get Y = (1/5)*X - 1. You should have followed that all I did was multiply everything by 1/5th. Whatever the coefficient of X is when you put the equation in point/slope form (Y=mX + b) is your slope (m).

In this case, m = 1/5. That is your slope.

Put it in y = mx + b format (you want to isolate y)

5y = x - 5

y = (x-5) / 5

y = x/5 - 1

y=1/5x-1

slope is dy/dx= 1/5.

make a drawing and you will understand it better.