Trigonometric functions HELP PLEASE?

You should get...

1. sin(x) = √(3)/2

cos(x) = ½

Hence, we obtain:

sec(x) = 2

sec(arcsin(√(3)/2)) = 2

2. tan(x) = √(3)/7

sin(x) = √3

cos(x) = 7

We obtain:

cos(arctan(√(3)/7)) = 7

3. sin(arcsin(√(3)/2)) = √(3)/2

I hope this helps!

sec x = 1/sin x so that would be 2/sqrt(3) = 2/3 sqrt(3)

tan u = sqrt(3)/7 = sin(u)/cos(u)

cos^2 u + sin^2 u = 1

sin(u) = sqrt(3)/7 cos u

cos^2(u) ( 1 + 3/49 ) = 1

cos u = sqrt(7/sqrt(52))

For the last one, if you can not answer it then I think there is no hope for you in math; try going to art school! (I know you can do the sin of the inverse sin, when it is in the first quadrant. If you are still asleep with it, maybe try drawing a picture.)

mad