Help with Equivalence and Simplifying Math Problem?

Question

Hey I need some help on a question on my math homework.
1. Which expression is equivalent to 3(2n+1)+4(n-2)
A. 10n+1
B. 10n-1
C.10n-7
D. 10n-5

2. -1/4(-4+2p)

Please explain how you find the answers to both of these. Don't forgot the PEMDAS rule. And the 1/4 in question 2 is a fraction. Please help!

Once you have the answer please explain to me how you got it also.

Si Yu Lim · Answer

answer for question 1 is D.. because 3(2n+1)=6n+3 and 4(n-2)=4n-8 just write 6n+3+4n-8 simplify it..

question 2 is 1-1/2p

since for -1/4 and -4, both are negative no.s, negative negative is positive so 1/4 of 4 is 1. 2p*-1/4 is -1/2p so the answer is 1-1/2p

Jimslaw · Answer

i only got d first answer which is the D. Dis is how i got it:first i expand 6n+3+4n-8=0,then i collect like terms 6n+4n=8-3,then i equate 6+4=10n,8-3=5 i.e 10n=5,n=10/5. n is 2.

Anonym · Answer

1) 3(2n + 1) + 4(n - 2)
open bracket
6n + 3 + 4n - 8
collect like terms
10n - 5 (ans = D)

2) -1(-4 + 2p)/4
open bracket
4/4 - 2p/4
1 - p/2 (ans)

Pauline Kramer · Answer

1 3(2n+1)=4(n-2)  us distrbute property=
6n+3+4n-8  combine like terms
10n-5    ans is d...

-1/4(-4+2p)  distrbute property  watch your signs....-1/4*-4+-2/4p 2/4 reduced is 1/2....
+1-1/2p 

tried to explain -*-=p0sitive  -*+=-  hope that helps..
final answer   1-1/2p

Help with Equivalence and Simplifying Math Problem?

4 Antworten