Initializing struct member array in C?

Question

/*
I have this structure, and in it is an array, and I can not seem initialize the array without getting compile errors.

this is basically what I'm trying to do looks like:
*/

struct foo {
    int bar[8] = { 1,2,3,4,5,6,7,8, };
};

Anonym · Accepted Answer

You misses definition and initialization: The correct looks like:

struct foo {
  int bar[8];
} x = { { 1,2,3,4,5,6,7,8 } };

//Now you can access like this:
x.bar[1];

Thx. Hope it is useful

More: you can only initialize a variable not a structure.

/ucmapi (http://www.ucmapi.com)

froman · Answer

it is between the relaxing factors of C programming. A char array in C is terminated by ability of technique of a null personality, escaped as ''. The char array could also be terminated by ability of making use of the dimensions of the array notwithstanding there's no such ensure in C. for this reason causing a lot of mistakes the position the array is accessed out of bounds. So by using initialising your structure with 0 you're putting a null ('') in component 0 of list and a nil in age. The null in component 0 shows that your char array has a usable length of 0. have relaxing.

Oliver · Answer

Hmm... I have done a bit of classes in C++ and if what they say that the only difference between classes and structures is that the members in structures are public by default and the member in classes are private in default, then you can use constructors. 
Sample code:
struct somestruct{
int someint[5];
somestruct{ 
someint[0] = ...;
//and so on... use a loop for big arrays :)
}
}

Initializing struct member array in C?

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