Through a sphere, a cylindrical hole of radius 3ft is drilled. What is the volume of the part remaining?

4/3 pi r^3 - pi r^2 h

Subtract the volume of cylinder from vol. of sphere..you didnt provide all information like height of cylinder, radius of sphere!

volume of the remainder sphere (holed one) is given via (4/3)(22/7)R^3 -- volume bumped off = (4/3)(22/7)R^3 -- [ volume of a cylinder of radius 2 and height 2 sqrt(R^2 -- 2^2) + volume of two segments of sphere subtending attitude 2 arcsin(2/R) on the centre] = (4/3)(22/7)R^3 -- [ (22/7)*2^3 sqrt(R^2 -- 4) + 2{ (pi/6) (3*2^2 + h^2)h}] the place h = R -- sqrt(r^2 -- 2^2)

you need the radius of sphere

the remaining volume is

V=22/7(4/3R^3-18(R^2-9)^1/2)

THIS WILL GIVE THE APPROXIMATE VOLUME.

not enough information