Factoring: I Need Math Help :(?

heyy so pretty much you want two numbers that equals a multiplied by c, but adds up to b.

now, a= the first term

b=the second term

c=third term.

you wanna take the first term and the last term and multiply the coefficients. for example in 4x(squared)+x-3=0, you would want to take the 4 and -3 and multiply them; so you would get -12. now you gotta find 2 numbers that will add up to +1 and when multiply will equal -12.

the two 2 numbers are +4 and -3. (youll get it with just practicing)

now add x infront of the two numbers you just found it.

so the answer is (x+4)(x-3)

if you need anymore help just email me :) and good luck.

a million. ingredient thoroughly: x^2 + 10x + 25 A) (x + 5)(x - 5) B) (x + 5)(x + 5) C) (x - 5)(x - 5) D) (x + 25)(x + a million) answer is B. x*x =x^2; 5*5=25; 5*x+5*x =10x 2. ingredient thoroughly: 3x^2 - 12 A) 3(x^2 - 4) B) 3(x + 2)(x + 2) C) 3(x + 2)(x - 2) D) (x + 2)(x - 2) answer is C. A is right yet did no longer pass a procedures adequate. x^2-4 could be factored to (x+4)(x-4). 3. ingredient thoroughly: 2x^2 - x - 10 A)(2x - 5)(x + 2) B) (2x + 5)(x - 2) C) (2x + 5)(x + 2) D) (2x - 5)(x - 2) answer is A. 2x*x =2x^2; (-5)(2)=-10;(-5)x +(2x)2 = -x 4. Simplify thoroughly: (4x -8) / (x-2) A) 4(x-2) / (x-2) B) 4 C) 8 D) 3x+4 answer is B. A did no longer cancel the x-2 words to get 4. this is going to that x will no longer be able to be equivalent to 2 or you would be dividing by utilising 0 that's a no-no

You just have to be sure the first terms in each factor multiply to come out the first term in the quadratic. It can involve some trial and error especially when the coefficient has several possible factors, like 8 (could be 1x and 8x; 2x and 4x, 4x and 2x, or 8x and 1x)

So make a guess, and put in the correct signs, then guess for the last term factors and FOIL it out to see how good your guess was.

I'll try #1

(4x + 3)(2x - 1) = 8x^2 - 4x + 6x - 1 = 8x^2 + 2x - 3

right numbers but wrong sign so switch the signs: (4x - 3)(2x + 1)

#3: (2x + 3)(2x - 1) = 4x^2 - 2x + 6x - 3 = 4x^2 + 4x - 3 not close

second try: (4x + 3)(x - 1) = 4x^2 - 4x + 3x - 3 = 4x^2 - x - 3

again right numbers wrong sign so switch signs: (4x - 3)(x + 1)

-1/2 and 3/4

2 and 3/9

-1 and 3/4

3/4 and -3

3/9 and 4/6

-1/2 and -2

8x(squared)-2x-3=0

(4x-3)(2x+1)

x=3/4 and x= -1/2

3x(squared)-5x-2=0

(3x+1)(x-2)

x= -1/3 and x=2

4x(squared)+x-3=0

(4x-3)(x+1)

x=3/4 and x= -1

4x(squared)+9x-9=0

(4x-3)(x+3)

x=3/4 and x= -3

9x(squared)+3x-2=0

(3x+2)(3x-1)

x= -2/3 and x= 1/3

2x(squared)+5x+2=0

(2x+1)(x+2)

x= -1/2 and x= -2