Calculus- Evaluate the definite integral?

This is going to look funny, because I don't know how to do an integral sign.

(integral from 0 to pi/4) 2sec^2(x) dx

=2 (integral from 0 to pi/4) sec^2(x) dx

the derivative of tan(x) is sec^2(x), so

=2 tan(x) when x goes from 0 to pi/4

=2(tan(pi/4)-tan(0))

=2(1-0)

=2

INT 2sec^2(x) dx from x = 0 to x = pi/4

Note that the integral of sec^2(x) is tan(x)

Integral evaluates to 2[tan(x)] from x = 0 to x = pi/4

= 2(tan(pi/4) - tan(0))

= 2

Int (0 to pi/4) 2sec^(x) dx =?

Int 2sec^2(x) dx = 2tan x + C (trigonometric Integrals list)

2tan x (0 to pi/4) = 2tan x(pi/4) - 2tan(0)

= 2((sin(pi/4))/(cos(pi/4)) - 2(sin(0))/(cos(0))

= 2((sqrt(2)/2))(sqrt(2)/(2)) - 0

= 2(1)

= 2 (answer)