What is the molarity of 60% KOH?

I do not really understand the question, but if 45%KOH is 11.5M.

then 60%KOH = 60/45*11.5 = 15.3M

If 45% KOH equals 11.5M, then 60% KOH must equal _____.

Explanation:

Assuming the KOH is in a 1 L flask, the moles of the 45% KOH will be 11.5 moles. The molar mass of KOH is 56.1 g/mol. Next, find the mass of 45% KOH. Mass = 56.1 g/mol X 11.5 moles = 645 g

If 45% = 645 g, then 60% = 4/3 * 645 g = 860 g

Now calculate the molarity of 60% KOH. Moles = 860 g / 56.1 g/mol = 15.3 mol. Since the KOH is in a 1 L flask, the molarity = 15.3 mol / 1 L = 15.3 M.

Therefore, the molarity of a 60% solid KOH is 15.3 M.

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