How many Cubic Centimeters volume in the universe we can see?

If the furthest observable objects are 14 billion (14000000000) light years away,

the size of the observable universe must be (4/3) x pi x 14 billion ^ 3

= 3.66 x 10^30 cubic light years.

One light year = 9.46 x 10^17 cm (speed of light in m/s x no. of seconds in a year x 100)

One cubic light year = 8.47 x 10^53 cm^3 (cm in a light year cubed)

10^30 cubic light years = 8.47x10^53 x 3.66x10^30

= 3.1 x 10^84 cm^3

so the observable universe is about

3 100 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 cm^3

The comoving distance from Earth to the edge of the visible universe (also called particle horizon) is about 14 billion parsecs (46.5 billion light-years) in any direction.[2] This defines a lower limit on the comoving radius of the observable universe, although as noted in the introduction, it's expected that the visible universe is somewhat smaller than the observable universe since we only see light from the cosmic microwave background radiation that was emitted after the time of recombination, giving us the spherical surface of last scattering (gravitational waves could theoretically allow us to observe events that occurred earlier than the time of recombination, from regions of space outside this sphere). The visible universe is thus a sphere with a diameter of about 28 billion parsecs (about 93 billion light-years). Since space is roughly flat, this size corresponds to a comoving volume of about

\frac{4}{3} \times \pi \times \mathrm{R}^3 = 4 \times 10^{32}\text{ ly}^3

or about 3×10^80 cubic meters.

about three fitty. And thats when I knew it was the Loch ness monster answering the question. So I told him to get his own Cubic Centimeters. He said ok , but before we left he ask could I get about....three fitty