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How is the decay energy for Uranium derived?
In fission energy calculations, Uranium fission is given as 200MeV/fission. How is this value derived? What is the corresponding value for Plutonium? Is it simply the mean Q-values of all the fission product reactions weighted by their probabilities?
http://hyperphysics.phy-astr.gsu.edu/Hbase/nucene/...
Found my answer - it is the average energy released from all possible U235 fission products - but an individual fission may release more or less.
Someone write it and I'll pick as best answer.
3 Antworten
- vor 1 JahrzehntBeste Antwort
it is the average energy released from all possible U235 fission products - but an individual fission may release more or less.
Quelle(n): :D - vor 1 Jahrzehnt
The fission of uranium will produce 2 daughter particles which are more stable that the original mother particle. This is the energy released. It can also be thought of as the lower binding energy's for daughter particles, lower than the over all binding energy for uranium. It really adds up to quite a lot of energy compared to the size of a sample which is why nuclear energy is so attractive.
- Terry RLv 6vor 1 Jahrzehnt
The energy is derived from converting mass to energy. The mass of the products is less than that of the reactants. The energy of the bombarding neutrons is negligible. So there it is. The derivation of the energy produced in fission is the mass difference.
Quelle(n): I teach physics, and a former radiation worker.
