principle of dominance??

It depends if speckled is a dominant or reccessive trait.

Given A=brown dominant and a=white recessive and Aa=speckled then here is an example of the principle:

Aa(mother)+Aa(father)=25% chance of each below

AA =brown

Aa =speckled

Aa =speckled

aa =white

So 25%=AA, 25%=aa, and Aa+Aa=50%

So in that case it would be 50% chance of speckled

hope that helps

This question cannot really be answered without the relevent genotypes of the animals. However it depends on the dominance of the alleles:

In order for chicks to be speckled, I believe it must be a result of co-dominance (black and white are both dominant so when combined they produce speckled).

Therfore, each chick should have the genotype BW.

BW x BW produces BB, WW, BW, BW.

Therefore there is a 50% chance of chicks being speckled, 25% chance them being white and 25% them being black.

By the way, the answer from the person above does not work because Aa would not be speckled as the A is dominant over the a so the offspring would be brown in his example - sorry.

Hope this helps!

1 C We can eliminate all other choices because we know for a fact they're not true. For any trait, there are a recessive, represented by a lower case, and a dominant, represented by capitals. #2 B I'm pretty sure this is the answer, but not completely. It's very reasonable because in order for a trait to appear, it has to be dominant, or homozygous recessive. The other choices don't suggest a homozygous recessive and are irreverent. Hope this helps, good luck!